Re: ---> Bờm

Posted by B ..73..180.33 on Jun 13, 2020 at 20:31:21:

In Reply to: Re: ---> Bờm posted by ch on Jun 13, 2020 at 20:17:40:

ha ha ha ha

{\displaystyle i\hbar {\frac {\partial }{\partial t}}|\psi (t)\rangle ={\hat {H}}|\psi (t)\rangle }

Schrödinger equation


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